@šHHÚ(˙á˙âůFG(üHHÚ(d'@xxxx˙€L˜ä ˙UNIT 15˙€L˜ä ˙LAB ACTIVITY 2˙€L˜ä ˙LAB REPORT SHEET˙€L˜ä €L˜ä 5 ˙STUDENT _______________ LAB GROUP _____________€L˜ä €L˜ä  ˙ _______________€L˜ä €L˜ä 5 ˙ _______________ DATE __________________€L˜ä €L˜ä  ˙ €L˜ä  ˙PROCEDURE:€L˜ä €L˜ä < ˙ A. 3/8" BALL BEARING DIAMETER = ____________INCHES€L˜ä €L˜ä A ˙ 3/8" BALL BEARING DIAMETER = ____________CENTIMETERS€L˜ä L ˙ (TO NEAREST 0.001)€L˜ä F ˙ B. VOLUME OF 3/8" BALL BEARING = ____________CM ˙3 ˙€L˜ä €L˜ä 1 ˙ (SHOW FORMULA AND CALCULATIONS) ˙€L˜ä €L˜ä €L˜ä  ˙  ˙€L˜ä  ˙  ˙€L˜ä E ˙ WHAT DIMENSION OF THE SPHERE DID YOU MEASURE? _________ ˙€L˜ä €L˜ä C ˙ C. INITIAL VOLUME OF WATER MEASURED = __________mL ˙€L˜ä €L˜ä A ˙ D. FINAL VOLUME OF WATER MEASURED = ___________mL ˙€L˜ä €L˜ä A ˙ E. CHANGE OR DIFFERENCE IN VOLUME = ____________mL ˙€L˜ä 9 ˙ (SHOW HOW DIFFERENCE IS DETERMINED) ˙€L˜ä €L˜ä  ˙  ˙€L˜ä L ˙ AVERAGE VOLUME OF ONE BALL BEARING =  $˙CHANGE IN VOLUME ˙€L˜ä 7 $˙  ˙ NO. OF BALL BEARINGS€L˜ä €L˜ä + ˙ = _________ = _____mL€L˜ä 0 ˙ 5€L˜ä €L˜ä 5 ˙ 1 mL = 1 CM ˙3 ˙ €L˜ä  ˙ €L˜ä N ˙ AVERAGE VOLUME OF 3/8" BALL BEARING = _________CM ˙3 ˙€L˜ä €L˜ä €L˜ä €L˜ä €L˜ä €L˜ä D ˙ F. DIFFERENCE BETWEEN CALCULATED (STEP B) AND MEASURED ˙€L˜ä > ˙  ˙(STEP E) VOLUME = __________CM ˙3 ˙€L˜ä  ˙  ˙ €L˜ä  ˙ (SHOW ALL WORK)€L˜ä €L˜ä > ˙ G. CALCULATED AVERAGE RADIUS OF BALL BEARING = _____CM€L˜ä €L˜ä # ˙ (SHOW FORMULA AND WORK)€L˜ä €L˜ä €L˜ä €L˜ä ? ˙ ONE-HALF DIAMETER OF MEASURED BALL BEARING = ______CM€L˜ä €L˜ä 1 ˙ COMPARE MEASURED AND CALCULATED RADIUS.€L˜ä  ˙ €L˜ä - ˙ DIFFERENCE = _________CM€L˜ä €L˜ä €L˜ä , ˙ H. BB DIAMETER = ___________INCHES€L˜ä €L˜ä 1 ˙ BB DIAMETER = ___________CENTIMETERS€L˜ä 6 ˙ (TO NEAREST 0.001)€L˜ä €L˜ä 7 ˙ I. VOLUME OF BB = ____________CM ˙3 ˙€L˜ä  ˙  ˙€L˜ä > ˙ (SHOW FORMULA AND CALCULATIONS) ˙€L˜ä €L˜ä @ ˙ J. INITIAL VOLUME OF WATER MEASURED = __________mL ˙€L˜ä  ˙  ˙€L˜ä @ ˙ K. FINAL VOLUME OF WATER MEASURED = ___________mL ˙€L˜ä €L˜ä > ˙ L. CHANGE OR DIFFERENCE IN VOLUME = __________mL ˙€L˜ä 8 ˙ (SHOW HOW DIFFERENCE IS DETERMINED) ˙€L˜ä €L˜ä €L˜ä G ˙ AVERAGE VOLUME OF ONE BB =  $˙CHANGE IN VOLUME  ˙€L˜ä H ˙ NO. OF BB'S€L˜ä €L˜ä Y ˙ = ____________ = _______mL €L˜ä I ˙ 100€L˜ä 5 ˙ 1 mL = 1 CM ˙3 ˙ €L˜ä L ˙ AVERAGE VOLUME OF ONE BB = ____________CM ˙3 ˙€L˜ä €L˜ä €L˜ä €L˜ä  ˙  ˙€L˜ä N ˙  ˙M. ˙  ˙ DIFFERENCE BETWEEN CALCULATED (STEP I) VOLUME AND€L˜ä L ˙ MEASURED (STEP L) VOLUME = ___________CM ˙3 ˙€L˜ä €L˜ä  ˙ (SHOW ALL WORK)€L˜ä €L˜ä €L˜ä 2 ˙ N. CALCULATED AVERAGE RADIUS = _________CM€L˜ä % ˙ (SHOW FORMULA AND WORK)€L˜ä €L˜ä €L˜ä €L˜ä 9 ˙ ONE-HALF DIAMETER OF MEASURED BB = ________CM€L˜ä €L˜ä €L˜ä 9 ˙ COMPARE MEASURED AND CALCULATED RADIUS OF BB.€L˜ä €L˜ä 1 ˙ DIFFERENCE = __________CM€L˜ä €L˜ä €L˜ä < ˙ O. DIFFERENCE BETWEEN CALCULATED AND MEASURED VOLUME,€L˜ä 4 ˙ BALL BEARING = _________CM ˙3 ˙€L˜ä €L˜ä N ˙  ˙ DIFFERENCE BETWEEN CALCULATED AND MEASURED VOLUME,€L˜ä 4 ˙ BB = ________CM ˙3 ˙€L˜ä  ˙ €L˜ä ? ˙ DIFFERENCE BETWEEN AVERAGE RADIUS AND 1/2 OF MEASURED€L˜ä < ˙ DIAMETER, BALL BEARING = _________CM€L˜ä €L˜ä ? ˙ DIFFERENCE BETWEEN AVERAGE RADIUS AND 1/2 OF MEASURED€L˜ä 4 ˙ DIAMETER, BB = ___________CM€L˜ä €L˜ä €L˜ä # ˙ P. ________________________€L˜ä €L˜ä €L˜ä €L˜ä  ˙ €L˜ä €L˜ä  ˙  ˙€L˜ä  ˙ €L˜ä  ˙ €L˜ä  ˙  ˙€L˜ä  ˙  ˙€L˜ä €L˜ä €L˜ä  ˙